Solve (2x^5)(x^2-4x-1)

Evaluate

(2 x^{5}) (x^{2} - 4 x - 1)

To find the roots of the expression,set the expression equal to 0

(2 x^{5}) (x^{2} - 4 x - 1) = 0

Multiply the terms

2 x^{5} (x^{2} - 4 x - 1) = 0

Elimination the left coefficient

x^{5} (x^{2} - 4 x - 1) = 0

Separate the equation into 2 possible cases

x^{5} = 0 x^{2} - 4 x - 1 = 0

The only way a power can be 0 is when the base equals 0

x = 0 x^{2} - 4 x - 1 = 0

Solve the equation

More Steps

x = 0 x = 2 + 5 x = 2 - 5

Solution

x_{1} = 2 - 5, x_{2} = 0, x_{3} = 2 + 5

Alternative Form

x_{1} \approx - 0.236068, x_{2} = 0, x_{3} \approx 4.236068

Simplify the expression