Question
Solve the inequality
Solve the inequality by testing the values in the interval
Solve the inequality by separating into cases
Solve for x
x∈(−∞,2]∪[3,+∞)
Evaluate
(x−2)(x−3)≥0
Rewrite the expression
(x−2)(x−3)=0
Separate the equation into 2 possible cases
x−2=0x−3=0
Solve the equation
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Evaluate
x−2=0
Move the constant to the right-hand side and change its sign
x=0+2
Removing 0 doesn't change the value,so remove it from the expression
x=2
x=2x−3=0
Solve the equation
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Evaluate
x−3=0
Move the constant to the right-hand side and change its sign
x=0+3
Removing 0 doesn't change the value,so remove it from the expression
x=3
x=2x=3
Determine the test intervals using the critical values
x<22<x<3x>3
Choose a value form each interval
x1=1x2=25x3=4
To determine if x<2 is the solution to the inequality,test if the chosen value x=1 satisfies the initial inequality
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Evaluate
(1−2)(1−3)≥0
Simplify
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Evaluate
(1−2)(1−3)
Subtract the numbers
(−1)(1−3)
Remove the parentheses
−(1−3)
Subtract the numbers
−(−2)
When there is - in front of an expression in parentheses change the sign of each term of the expression and remove the parentheses
2
2≥0
Check the inequality
true
x<2 is the solutionx2=25x3=4
To determine if 2<x<3 is the solution to the inequality,test if the chosen value x=25 satisfies the initial inequality
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Evaluate
(25−2)(25−3)≥0
Simplify
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Evaluate
(25−2)(25−3)
Subtract the numbers
21(25−3)
Subtract the numbers
21(−21)
Multiplying or dividing an odd number of negative terms equals a negative
−21×21
To multiply the fractions,multiply the numerators and denominators separately
−2×21
Multiply the numbers
−41
−41≥0
Calculate
−0.25≥0
Check the inequality
false
x<2 is the solution2<x<3 is not a solutionx3=4
To determine if x>3 is the solution to the inequality,test if the chosen value x=4 satisfies the initial inequality
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Evaluate
(4−2)(4−3)≥0
Simplify
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Evaluate
(4−2)(4−3)
Subtract the numbers
2(4−3)
Subtract the numbers
2×1
Any expression multiplied by 1 remains the same
2
2≥0
Check the inequality
true
x<2 is the solution2<x<3 is not a solutionx>3 is the solution
The original inequality is a nonstrict inequality,so include the critical value in the solution
x≤2 is the solutionx≥3 is the solution
Solution
x∈(−∞,2]∪[3,+∞)
Show Solution
