Solve 2x^2+38x+10

Evaluate

2 x^{2} + 38 x + 10

To find the roots of the expression,set the expression equal to 0

2 x^{2} + 38 x + 10 = 0

Substitute a= 2,b= 38 and c= 10 into the quadratic formula x = \frac{- b \pm b ^{2} - 4 a c}{2 a}

x = \frac{- 38 \pm 3 8 ^{2} - 4 \times 2 \times 10}{2 \times 2}

Simplify the expression

x = \frac{- 38 \pm 3 8 ^{2} - 4 \times 2 \times 10}{4}

Simplify the expression

More Steps

x = \frac{- 38 \pm 1364}{4}

Simplify the radical expression

More Steps

x = \frac{- 38 \pm 2 341}{4}

Separate the equation into 2 possible cases

x = \frac{- 38 + 2 341}{4} x = \frac{- 38 - 2 341}{4}

Simplify the expression

More Steps

x = \frac{- 19 + 341}{2} x = \frac{- 38 - 2 341}{4}

Simplify the expression

More Steps

x = \frac{- 19 + 341}{2} x = - \frac{19 + 341}{2}

Solution

x_{1} = - \frac{19 + 341}{2}, x_{2} = \frac{- 19 + 341}{2}

Alternative Form

x_{1} \approx - 18.733093, x_{2} \approx - 0.266907

2x^2+38x+10