Solve B^45501-1-1

Question

Simplify the expression

5501 B^{4} - 2

Evaluate

B^{4} \times 5501 - 1 - 1

Use the commutative property to reorder the terms

5501 B^{4} - 1 - 1

Solution

5501 B^{4} - 2

Show Solution

B_{1} = - \frac{4 2 \times 550 1 ^{3}}{5501}, B_{2} = \frac{4 2 \times 550 1 ^{3}}{5501}

Alternative Form

B_{1} \approx - 0.138085, B_{2} \approx 0.138085

Evaluate

B^{4} \times 5501 - 1 - 1

To find the roots of the expression,set the expression equal to 0

B^{4} \times 5501 - 1 - 1 = 0

Use the commutative property to reorder the terms

5501 B^{4} - 1 - 1 = 0

Subtract the numbers

5501 B^{4} - 2 = 0

Move the constant to the right-hand side and change its sign

5501 B^{4} = 0 + 2

Removing 0 doesn't change the value,so remove it from the expression

5501 B^{4} = 2

Divide both sides

\frac{5501 B ^{4}}{5501} = \frac{2}{5501}

Divide the numbers

B^{4} = \frac{2}{5501}

Take the root of both sides of the equation and remember to use both positive and negative roots

B = \pm 4 \frac{2}{5501}

Simplify the expression

More Steps

Evaluate

4 \frac{2}{5501}

To take a root of a fraction,take the root of the numerator and denominator separately

\frac{4 2}{4 5501}

Multiply by the Conjugate

\frac{4 2 \times 4 550 1 ^{3}}{4 5501 \times 4 550 1 ^{3}}

The product of roots with the same index is equal to the root of the product

\frac{4 2 \times 550 1 ^{3}}{4 5501 \times 4 550 1 ^{3}}

Multiply the numbers

More Steps

Evaluate

45501 \times 4 550 1^{3}

The product of roots with the same index is equal to the root of the product

4 5501 \times 550 1^{3}

Calculate the product

4 550 1^{4}

Reduce the index of the radical and exponent with 4

5501

\frac{4 2 \times 550 1 ^{3}}{5501}

B = \pm \frac{4 2 \times 550 1 ^{3}}{5501}

Separate the equation into 2 possible cases

B = \frac{4 2 \times 550 1 ^{3}}{5501} B = - \frac{4 2 \times 550 1 ^{3}}{5501}

Solution

B_{1} = - \frac{4 2 \times 550 1 ^{3}}{5501}, B_{2} = \frac{4 2 \times 550 1 ^{3}}{5501}

Alternative Form

B_{1} \approx - 0.138085, B_{2} \approx 0.138085

Show Solution