Question
Factor the expression
Factor
(x+3)(x+12)
Evaluate
x2+15x+36
Rewrite the expression
x2+(12+3)x+36
Calculate
x2+12x+3x+36
Rewrite the expression
x×x+x×12+3x+3×12
Factor out x from the expression
x(x+12)+3x+3×12
Factor out 3 from the expression
x(x+12)+3(x+12)
Solution
(x+3)(x+12)
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Find the roots
Find the roots of the algebra expression
x1=−12,x2=−3
Evaluate
x2+15x+36
To find the roots of the expression,set the expression equal to 0
x2+15x+36=0
Factor the expression
More Steps
Evaluate
x2+15x+36
Rewrite the expression
x2+(12+3)x+36
Calculate
x2+12x+3x+36
Rewrite the expression
x×x+x×12+3x+3×12
Factor out x from the expression
x(x+12)+3x+3×12
Factor out 3 from the expression
x(x+12)+3(x+12)
Factor out x+12 from the expression
(x+3)(x+12)
(x+3)(x+12)=0
When the product of factors equals 0,at least one factor is 0
x+3=0x+12=0
Solve the equation for x
More Steps
Evaluate
x+3=0
Move the constant to the right-hand side and change its sign
x=0−3
Removing 0 doesn't change the value,so remove it from the expression
x=−3
x=−3x+12=0
Solve the equation for x
More Steps
Evaluate
x+12=0
Move the constant to the right-hand side and change its sign
x=0−12
Removing 0 doesn't change the value,so remove it from the expression
x=−12
x=−3x=−12
Solution
x1=−12,x2=−3
Show Solution