Question
Function
Find the vertex
Find the axis of symmetry
Evaluate the derivative
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(0,−1000000)
Evaluate
y=(x2−2000)×500
Simplify
y=500(x2−2000)
Write the quadratic function in standard form
y=500x2−1000000
Find the x-coordinate of the vertex by substituting a=500 and b=0 into x = −2ab
x=−2×5000
Solve the equation for x
x=0
Find the y-coordinate of the vertex by evaluating the function for x=0
y=500×02−1000000
Calculate
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Evaluate
500×02−1000000
Calculate
500×0−1000000
Any expression multiplied by 0 equals 0
0−1000000
Removing 0 doesn't change the value,so remove it from the expression
−1000000
y=−1000000
Solution
(0,−1000000)
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Testing for symmetry
Testing for symmetry about the origin
Testing for symmetry about the x-axis
Testing for symmetry about the y-axis
Not symmetry with respect to the origin
Evaluate
y=(x2−2000)500
Simplify the expression
y=500(x2−2000)
To test if the graph of y=500(x2−2000) is symmetry with respect to the origin,substitute -x for x and -y for y
−y=500((−x)2−2000)
Simplify
−y=500(x2−2000)
Change the signs both sides
y=−500(x2−2000)
Solution
Not symmetry with respect to the origin
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Identify the conic
Find the standard equation of the parabola
Find the vertex of the parabola
Find the focus of the parabola
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x2=5001(y+1000000)
Evaluate
y=(x2−2000)×500
Simplify
y=500(x2−2000)
Calculate
y=500x2−1000000
Swap the sides of the equation
500x2−1000000=y
Move the constant to the right-hand side and change its sign
500x2=y−(−1000000)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
500x2=y+1000000
Multiply both sides of the equation by 5001
500x2×5001=(y+1000000)×5001
Multiply the terms
x2=(y+1000000)×5001
Multiply the terms
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Evaluate
(y+1000000)×5001
Apply the distributive property
y×5001+1000000×5001
Use the commutative property to reorder the terms
5001y+1000000×5001
Multiply the numbers
5001y+2000
x2=5001y+2000
Solution
x2=5001(y+1000000)
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Solve the equation
Solve for x
Solve for y
x=505y+5000000x=−505y+5000000
Evaluate
y=(x2−2000)×500
Simplify
y=500(x2−2000)
Swap the sides of the equation
500(x2−2000)=y
Divide both sides
500500(x2−2000)=500y
Divide the numbers
x2−2000=500y
Move the constant to the right side
x2=500y+2000
Add the terms
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Evaluate
500y+2000
Reduce fractions to a common denominator
500y+5002000×500
Write all numerators above the common denominator
500y+2000×500
Multiply the numbers
500y+1000000
x2=500y+1000000
Take the root of both sides of the equation and remember to use both positive and negative roots
x=±500y+1000000
Simplify the expression
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Evaluate
500y+1000000
To take a root of a fraction,take the root of the numerator and denominator separately
500y+1000000
Simplify the radical expression
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Evaluate
500
Write the expression as a product where the root of one of the factors can be evaluated
100×5
Write the number in exponential form with the base of 10
102×5
The root of a product is equal to the product of the roots of each factor
102×5
Reduce the index of the radical and exponent with 2
105
105y+1000000
Multiply by the Conjugate
105×5y+1000000×5
Calculate
10×5y+1000000×5
Calculate
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Evaluate
y+1000000×5
The product of roots with the same index is equal to the root of the product
(y+1000000)×5
Calculate the product
5y+5000000
10×55y+5000000
Calculate
505y+5000000
x=±505y+5000000
Solution
x=505y+5000000x=−505y+5000000
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Rewrite the equation
r=1000cos2(θ)sin(θ)−1999999999cos2(θ)+2000000001r=1000cos2(θ)sin(θ)+1999999999cos2(θ)+2000000001
Evaluate
y=(x2−2000)×500
Simplify
y=500(x2−2000)
Move the expression to the left side
y−500x2=−1000000
To convert the equation to polar coordinates,substitute x for rcos(θ) and y for rsin(θ)
sin(θ)×r−500(cos(θ)×r)2=−1000000
Factor the expression
−500cos2(θ)×r2+sin(θ)×r=−1000000
Subtract the terms
−500cos2(θ)×r2+sin(θ)×r−(−1000000)=−1000000−(−1000000)
Evaluate
−500cos2(θ)×r2+sin(θ)×r+1000000=0
Solve using the quadratic formula
r=−1000cos2(θ)−sin(θ)±sin2(θ)−4(−500cos2(θ))×1000000
Simplify
r=−1000cos2(θ)−sin(θ)±1999999999cos2(θ)+2000000001
Separate the equation into 2 possible cases
r=−1000cos2(θ)−sin(θ)+1999999999cos2(θ)+2000000001r=−1000cos2(θ)−sin(θ)−1999999999cos2(θ)+2000000001
Use b−a=−ba=−ba to rewrite the fraction
r=1000cos2(θ)sin(θ)−1999999999cos2(θ)+2000000001r=−1000cos2(θ)−sin(θ)−1999999999cos2(θ)+2000000001
Solution
r=1000cos2(θ)sin(θ)−1999999999cos2(θ)+2000000001r=1000cos2(θ)sin(θ)+1999999999cos2(θ)+2000000001
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