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[(2 Xi^2)^2 4alpha beta]^2=16alpha beta(1 Alpha beta)^2
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[(2-xi^2)^2-4alpha beta]^2=16alpha beta(1-alpha beta)^2
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Pertanyaan
[(
2
−
x
i
2
)
2
−
4
a
lp
hab
e
t
a
]
2
=
16
a
lp
hab
e
t
a
(
1
−
a
lp
hab
e
t
a
)
2
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