(x-y)^2=x+y-1

Pertanyaan yang Sering Diajukan

• $\text{Selesaikan untuk }x$ ${\left(x-y\right)}^2=x+y-1$

  

  $$\begin{array}{rl}& x=\frac{2y+1+\sqrt{8y-3}}{2}\\ & x=\frac{2y+1-\sqrt{8y-3}}{2}\end{array}$$

• $\text{Selesaikan untuk }y$ ${\left(x-y\right)}^2=x+y-1$

  

  $$\begin{array}{rl}& y=\frac{2x+1+\sqrt{8x-3}}{2}\\ & y=\frac{2x+1-\sqrt{8x-3}}{2}\end{array}$$

• Pengujian simetri terhadap titik asal ${\left(x-y\right)}^2=x+y-1$

  

  $$\text{Tidak simetris terhadap titik asal.}$$

• Pengujian simetri terhadap sumbu x ${\left(x-y\right)}^2=x+y-1$

  

  $$\text{Tidak simetris terhadap sumbu x.}$$

• Pengujian simetri terhadap sumbu y ${\left(x-y\right)}^2=x+y-1$

  

  $$\text{Tidak simetris terhadap sumbu y.}$$

• Tulis ulang dalam bentuk polar ${\left(x-y\right)}^2=x+y-1$

  

  $$\begin{array}{rl}& r=\frac{\cos \left(\theta \right)+\sin \left(\theta \right)+\sqrt{-3+5\sin \left(2\theta \right)}}{2-2\sin \left(2\theta \right)}\\ & r=\frac{\cos \left(\theta \right)+\sin \left(\theta \right)-\sqrt{-3+5\sin \left(2\theta \right)}}{2-2\sin \left(2\theta \right)}\end{array}$$

• $\text{Carilah turunan terhadap }x$ ${\left(x-y\right)}^2=x+y-1$

  

  $$\frac{dy}{dx}=\frac{1-2x+2y}{-2x+2y-1}$$

• $\text{Carilah turunan terhadap }y$ ${\left(x-y\right)}^2=x+y-1$

  

  $$\frac{dx}{dy}=\frac{1+2x-2y}{2x-2y-1}$$

• Hilangkan suku xy dengan cara memutar. ${\left(x-y\right)}^2=x+y-1$

  

  $${\left(y^{\prime }\right)}^2=\frac{\sqrt{2}}{2}\left(x^{\prime }-\frac{1}{\sqrt{2}}\right)$$