begin{array l x = sqrt{t^{2 + 1} } y = ln{ ( t + sqrt{t^{2 + 1} )} } endarray .

常见问题解答

• 写出矩形方程 $\{\begin{array}{l}x=\sqrt{t^2+1}\\ y=\ln \left(t+\sqrt{t^2+1}\right)\end{array}$

  

  $$\begin{array}{rl}& y=\ln \left(\sqrt{x^2-1}+\left|x\right|\right)\\ & y=\ln \left(-\sqrt{x^2-1}+\left|x\right|\right)\end{array}$$

• 求参数导数 $\{\begin{array}{l}x=\sqrt{t^2+1}\\ y=\ln \left(t+\sqrt{t^2+1}\right)\end{array}$

  

  $$\frac{dy}{dx}=\frac{1}{t}$$