[beginarrayl 1&2&32&4&61&1&1endarray]

常见问题解答

• 求该行列式的值 \(\left[\begin{array}{l} {1}&{2}&{3}\\{2}&{4}&{6}\\{1}&{1}&{1}\end{array}\right]\)

  

  $$0$$

• 求逆矩阵 \(\left[\begin{array}{l} {1}&{2}&{3}\\{2}&{4}&{6}\\{1}&{1}&{1}\end{array}\right]\)

  

  $$\text{Does not exist}$$

• 求矩阵转置 \(\left[\begin{array}{l} {1}&{2}&{3}\\{2}&{4}&{6}\\{1}&{1}&{1}\end{array}\right]\)

  

  $$\left[\begin{array}{lll}1& 2& 1\\ 2& 4& 1\\ 3& 6& 1\end{array}\right]$$

• 求特征值 \(\left[\begin{array}{l} {1}&{2}&{3}\\{2}&{4}&{6}\\{1}&{1}&{1}\end{array}\right]\)

  

  $${\lambda }_1=3-\sqrt{13},{\lambda }_2=0,{\lambda }_3=3+\sqrt{13}$$

• 求行梯形形式 \(\left[\begin{array}{l} {1}&{2}&{3}\\{2}&{4}&{6}\\{1}&{1}&{1}\end{array}\right]\)

  

  $$\left[\begin{array}{lll}1& 2& 3\\ 0& -1& -2\\ 0& 0& 0\end{array}\right]$$

• 求简化的行梯形形式 \(\left[\begin{array}{l} {1}&{2}&{3}\\{2}&{4}&{6}\\{1}&{1}&{1}\end{array}\right]\)

  

  $$\left[\begin{array}{lll}1& 0& -1\\ 0& 1& 2\\ 0& 0& 0\end{array}\right]$$