frac(2x^{2+3x-1)}((x-1)^{2(x+2))}

常见问题解答

• 解决方案 $\frac{\left(2x^2+3x-1\right)}{\left({\left(x-1\right)}^2\left(x+2\right)\right)}$

  

  $$\frac{2x^2+3x-1}{x^3-3x+2}$$

• 查找排除的值 $\frac{\left(2x^2+3x-1\right)}{\left({\left(x-1\right)}^2\left(x+2\right)\right)}$

  

  $$x=1,x=-2$$

• 使用部分分数分解重写 $\frac{\left(2x^2+3x-1\right)}{\left({\left(x-1\right)}^2\left(x+2\right)\right)}$

  

  $$\frac{4}{3{\left(x-1\right)}^2}+\frac{17}{9\left(x-1\right)}+\frac{1}{9\left(x+2\right)}$$

• 求代数表达式的根 $\frac{\left(2x^2+3x-1\right)}{\left({\left(x-1\right)}^2\left(x+2\right)\right)}$

  

  $$x_1=-\frac{3+\sqrt{17}}{4},x_2=\frac{-3+\sqrt{17}}{4}$$