begin{arraylx+y+z=62x-y+z=5x+2y-z=3endarray.

常见问题解答

• 使用替换法求解 $\{\begin{array}{l}x+y+z=6\\ 2x-y+z=5\\ x+2y-z=3\end{array}$

  

  $$\left(x,y,z\right)=\left(\frac{15}{7},\frac{11}{7},\frac{16}{7}\right)$$

• 使用消元法求解 $\{\begin{array}{l}x+y+z=6\\ 2x-y+z=5\\ x+2y-z=3\end{array}$

  

  $$\left(x,y,z\right)=\left(\frac{15}{7},\frac{11}{7},\frac{16}{7}\right)$$

• 使用 Gauss-Jordan 方法求解 $\{\begin{array}{l}x+y+z=6\\ 2x-y+z=5\\ x+2y-z=3\end{array}$

  

  $$\left(x,y,z\right)=\left(\frac{15}{7},\frac{11}{7},\frac{16}{7}\right)$$

• 使用克莱默规则求解 $\{\begin{array}{l}x+y+z=6\\ 2x-y+z=5\\ x+2y-z=3\end{array}$

  

  $$\left(x,y,z\right)=\left(\frac{15}{7},\frac{11}{7},\frac{16}{7}\right)$$