x + y + z = 6, 2x - y + z = 5, x + 2y - z = 3

常见问题解答

• 使用替换法求解 $x+y+z=6,2x-y+z=5,x+2y-z=3$

  

  $$\left(x,y,z\right)=\left(\frac{15}{7},\frac{11}{7},\frac{16}{7}\right)$$

• 使用消元法求解 $x+y+z=6,2x-y+z=5,x+2y-z=3$

  

  $$\left(x,y,z\right)=\left(\frac{15}{7},\frac{11}{7},\frac{16}{7}\right)$$

• 使用 Gauss-Jordan 方法求解 $x+y+z=6,2x-y+z=5,x+2y-z=3$

  

  $$\left(x,y,z\right)=\left(\frac{15}{7},\frac{11}{7},\frac{16}{7}\right)$$

• 使用克莱默规则求解 $x+y+z=6,2x-y+z=5,x+2y-z=3$

  

  $$\left(x,y,z\right)=\left(\frac{15}{7},\frac{11}{7},\frac{16}{7}\right)$$