lim _xgoes to 2(fracx^{4-4x^3+5x^2-4x+4}x^{4-4x^3+6x^2-8x+8})

常见问题解答

• 使用变换法求值 ${\lim }_{x\to 2}\left(\frac{x^4-4x^3+5x^2-4x+4}{x^4-4x^3+6x^2-8x+8}\right)$

  

  $$\frac{5}{6}$$

• 使用洛必达法则求值 ${\lim }_{x\to 2}\left(\frac{x^4-4x^3+5x^2-4x+4}{x^4-4x^3+6x^2-8x+8}\right)$

  

  $$\frac{5}{6}$$