fractan^{2alpha + 1}sec{alpha} = secalpha

常见问题解答

• $\text{求解 }\alpha$ $\frac{{\tan }^2\alpha +1}{\sec \alpha }=\sec \alpha$

  

  $$\alpha \ne \frac{\pi }{2}+k\pi ,k\in \mathbb{Z}$$

• 核实 $\frac{{\tan }^2\alpha +1}{\sec \alpha }=\sec \alpha$

  

  $$\text{为真}$$