Question
Evaluate the derivative
2x+2
Evaluate
dxd(x2+2x+5)
Use differentiation rule dxd(f(x)±g(x))=dxd(f(x))±dxd(g(x))
dxd(x2)+dxd(2x)+dxd(5)
Use dxdxn=nxn−1 to find derivative
2x+dxd(2x)+dxd(5)
Calculate
More Steps
![solution-arrow](../../wwwstatic/images/solution-arrow-down-1.svg)
Calculate
dxd(2x)
Use differentiation rule dxd(cf(x))=c×dxd(f(x))
2×dxd(x)
Use dxdxn=nxn−1 to find derivative
2×1
Any expression multiplied by 1 remains the same
2
2x+2+dxd(5)
Use dxd(c)=0 to find derivative
2x+2+0
Solution
2x+2
Show Solution
![solution-arrow](data:image/svg+xml;base64,PHN2ZyB3aWR0aD0iMTciIGhlaWdodD0iMTYiIHZpZXdCb3g9IjAgMCAxNyAxNiIgZmlsbD0ibm9uZSIgeG1sbnM9Imh0dHA6Ly93d3cudzMub3JnLzIwMDAvc3ZnIj4KPHBhdGggZD0iTTguNSAyLjY2Nzk3TDguNSAxMi42NjgiIHN0cm9rZT0id2hpdGUiIHN0cm9rZS13aWR0aD0iMS41IiBzdHJva2UtbGluZWNhcD0icm91bmQiIHN0cm9rZS1saW5lam9pbj0icm91bmQiLz4KPHBhdGggZD0iTTEyLjUgOC42Njc5N0w4LjUgMTIuNjY4TDQuNSA4LjY2Nzk3IiBzdHJva2U9IndoaXRlIiBzdHJva2Utd2lkdGg9IjEuNSIgc3Ryb2tlLWxpbmVjYXA9InJvdW5kIiBzdHJva2UtbGluZWpvaW49InJvdW5kIi8+Cjwvc3ZnPgo=)