Solve \left\{ \begin{array} { l } { x^2+y^2=6}\\ { 2x - ScanMath

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Type your math problem... \left\{ \begin{array} { l } { x^2+y^2=6}\\ { 2x^2-y^2=4} \end{array} \right.

Question

Solve the system of equations

Solve using the substitution method

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Solve using the elimination method

(x_{1}, y_{1}) = (- \frac{30}{3}, - \frac{2 6}{3}) (x_{2}, y_{2}) = (- \frac{30}{3}, \frac{2 6}{3}) (x_{3}, y_{3}) = (\frac{30}{3}, - \frac{2 6}{3}) (x_{4}, y_{4}) = (\frac{30}{3}, \frac{2 6}{3})

Evaluate

{x^{2} + y^{2} = 6 2 x^{2} - y^{2} = 4

Solve the equation for x

More Steps

{x = 6 - y^{2} \cup x = - 6 - y^{2} 2 x^{2} - y^{2} = 4

Evaluate

{x = 6 - y^{2} 2 x^{2} - y^{2} = 4 \cup {x = - 6 - y^{2} 2 x^{2} - y^{2} = 4

Calculate

More Steps

{x = \frac{30}{3} y = - \frac{2 6}{3} \cup {x = \frac{30}{3} y = \frac{2 6}{3} \cup {x = - 6 - y^{2} 2 x^{2} - y^{2} = 4

Calculate

More Steps

{x = \frac{30}{3} y = - \frac{2 6}{3} \cup {x = \frac{30}{3} y = \frac{2 6}{3} \cup {x = - \frac{30}{3} y = - \frac{2 6}{3} \cup {x = - \frac{30}{3} y = \frac{2 6}{3}

Rearrange the terms

{x = - \frac{30}{3} y = - \frac{2 6}{3} \cup {x = - \frac{30}{3} y = \frac{2 6}{3} \cup {x = \frac{30}{3} y = - \frac{2 6}{3} \cup {x = \frac{30}{3} y = \frac{2 6}{3}

Check the solution

More Steps

{x = - \frac{30}{3} y = - \frac{2 6}{3} \cup {x = - \frac{30}{3} y = \frac{2 6}{3} \cup {x = \frac{30}{3} y = - \frac{2 6}{3} \cup {x = \frac{30}{3} y = \frac{2 6}{3}

Check the solution

More Steps

{x = - \frac{30}{3} y = - \frac{2 6}{3} \cup {x = - \frac{30}{3} y = \frac{2 6}{3} \cup {x = \frac{30}{3} y = - \frac{2 6}{3} \cup {x = \frac{30}{3} y = \frac{2 6}{3}

Check the solution

More Steps

{x = - \frac{30}{3} y = - \frac{2 6}{3} \cup {x = - \frac{30}{3} y = \frac{2 6}{3} \cup {x = \frac{30}{3} y = - \frac{2 6}{3} \cup {x = \frac{30}{3} y = \frac{2 6}{3}

Check the solution

More Steps

{x = - \frac{30}{3} y = - \frac{2 6}{3} \cup {x = - \frac{30}{3} y = \frac{2 6}{3} \cup {x = \frac{30}{3} y = - \frac{2 6}{3} \cup {x = \frac{30}{3} y = \frac{2 6}{3}

Solution

(x_{1}, y_{1}) = (- \frac{30}{3}, - \frac{2 6}{3}) (x_{2}, y_{2}) = (- \frac{30}{3}, \frac{2 6}{3}) (x_{3}, y_{3}) = (\frac{30}{3}, - \frac{2 6}{3}) (x_{4}, y_{4}) = (\frac{30}{3}, \frac{2 6}{3})

Show Solution

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