写出矩形方程 y = 3 t + 2 , x = 2 t^{2}

x=\frac{2\left(y-2\right)^{2}}{9}

Solve y = 3 t + 2 , x = 2 t^2

求值

{y = 3 t + 2 x = 2 t^{2}

求导数 \frac{d y}{d x} ，先求 \frac{d x}{d t} 和 \frac{d y}{d t}

\frac{d}{d t} (y) = \frac{d}{d t} (3 t + 2) \frac{d}{d t} (x) = \frac{d}{d t} (2 t^{2})

求导数

More Steps

\frac{d y}{d t} = 3 \frac{d}{d t} (x) = \frac{d}{d t} (2 t^{2})

求导数

More Steps

\frac{d y}{d t} = 3 \frac{d x}{d t} = 4 t

Solution

\frac{d y}{d x} = \frac{3}{4 t}