begin{arraylx+y+z=62x-y+z=5x+2y-z=3endarray.

Preguntas Frecuentes

• Resuelve usando el método de sustitución $\{\begin{array}{l}x+y+z=6\\ 2x-y+z=5\\ x+2y-z=3\end{array}$

  

  $$\left(x,y,z\right)=\left(\frac{15}{7},\frac{11}{7},\frac{16}{7}\right)$$

• Resuelve usando el método de eliminación $\{\begin{array}{l}x+y+z=6\\ 2x-y+z=5\\ x+2y-z=3\end{array}$

  

  $$\left(x,y,z\right)=\left(\frac{15}{7},\frac{11}{7},\frac{16}{7}\right)$$

• Resolver usando el método de Gauss-Jordan $\{\begin{array}{l}x+y+z=6\\ 2x-y+z=5\\ x+2y-z=3\end{array}$

  

  $$\left(x,y,z\right)=\left(\frac{15}{7},\frac{11}{7},\frac{16}{7}\right)$$

• Resuelve usando la regla de Cramer $\{\begin{array}{l}x+y+z=6\\ 2x-y+z=5\\ x+2y-z=3\end{array}$

  

  $$\left(x,y,z\right)=\left(\frac{15}{7},\frac{11}{7},\frac{16}{7}\right)$$