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\left\{ \begin{array} { l } { \frac { x + 1 } { 3 } = \frac { y + 2 } { 4 } } \\ { \frac { x 3 } { 4 } \frac { y 3 } { 3 } = \frac { 1 } { 12 } } \end{array} \right.

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Type your math problem... \left\{ \begin{array} { l } { \frac { x + 1 } { 3 } = \frac { y + 2 } { 4 } } \\ { \frac { x - 3 } { 4 } - \frac { y - 3 } { 3 } = \frac { 1 } { 12 } } \end{array} \right.

Question

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(x, y) = (2, 2)

求值

{\frac{x + 1}{3} = \frac{y + 2}{4} \frac{x - 3}{4} - \frac{y - 3}{3} = \frac{1}{12}

求解 x 的方程

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{x = \frac{3 y + 2}{4} \frac{x - 3}{4} - \frac{y - 3}{3} = \frac{1}{12}

将 x 的给定值代入方程 \frac{x - 3}{4} - \frac{y - 3}{3} = \frac{1}{12}

\frac{\frac{3 y + 2}{4} - 3}{4} - \frac{y - 3}{3} = \frac{1}{12}

简化

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\frac{3 y - 10}{16} - \frac{y - 3}{3} = \frac{1}{12}

等式两边同时乘以LCD

(\frac{3 y - 10}{16} - \frac{y - 3}{3}) \times 48 = \frac{1}{12} \times 48

简化方程

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- 7 y + 18 = \frac{1}{12} \times 48

简化方程

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- 7 y + 18 = 4

将常量移到右侧

- 7 y = 4 - 18

减去数字

- 7 y = - 14

改变等式两边的符号

7 y = 14

两边同时除以

\frac{7 y}{7} = \frac{14}{7}

把这些数相除

y = \frac{14}{7}

把这些数相除

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y = 2

将 y 的给定值代入方程 x = \frac{3 y + 2}{4}

x = \frac{3 \times 2 + 2}{4}

计算

x = 2

计算

{x = 2 y = 2

检查解决方案

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{x = 2 y = 2

Solution

(x, y) = (2, 2)

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