Solve x^2+y^2=1 - ScanMath

Identify the conic

Find the radius of the circle

Find the center of the circle

r = 1

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Solve the equation

Solve for x

Solve for y

x = 1 - y^{2} x = - 1 - y^{2}

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Testing for symmetry

Testing for symmetry about the origin

Testing for symmetry about the x-axis

Testing for symmetry about the y-axis

Symmetry with respect to the origin

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Find the first derivative

Find the derivative with respect to x

Find the derivative with respect to y

\frac{d y}{d x} = - \frac{x}{y}

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Find the second derivative

Find the second derivative with respect to x

Find the second derivative with respect to y

\frac{d ^{2} y}{d x ^{2}} = - \frac{y ^{2} + x ^{2}}{y ^{3}}

Calculate

x^{2} + y^{2} = 1

Take the derivative of both sides

\frac{d}{d x} (x^{2} + y^{2}) = \frac{d}{d x} (1)

Calculate the derivative

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2 x + 2 y \frac{d y}{d x} = \frac{d}{d x} (1)

Calculate the derivative

2 x + 2 y \frac{d y}{d x} = 0

Move the expression to the right-hand side and change its sign

2 y \frac{d y}{d x} = 0 - 2 x

Removing 0 doesn't change the value,so remove it from the expression

2 y \frac{d y}{d x} = - 2 x

Divide both sides

\frac{2 y \frac{d y}{d x}}{2 y} = \frac{- 2 x}{2 y}

Divide the numbers

\frac{d y}{d x} = \frac{- 2 x}{2 y}

Divide the numbers

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\frac{d y}{d x} = - \frac{x}{y}

Take the derivative of both sides

\frac{d}{d x} (\frac{d y}{d x}) = \frac{d}{d x} (- \frac{x}{y})

Calculate the derivative

\frac{d ^{2} y}{d x ^{2}} = \frac{d}{d x} (- \frac{x}{y})

Use differentiation rules

\frac{d ^{2} y}{d x ^{2}} = - \frac{\frac{d}{d x} ( x ) \times y - x \times \frac{d}{d x} ( y )}{y ^{2}}

Use \frac{d}{d x} x^{n} = n x^{n - 1} to find derivative

\frac{d ^{2} y}{d x ^{2}} = - \frac{1 \times y - x \times \frac{d}{d x} ( y )}{y ^{2}}

Calculate the derivative

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\frac{d ^{2} y}{d x ^{2}} = - \frac{1 \times y - x \frac{d y}{d x}}{y ^{2}}

Any expression multiplied by 1 remains the same

\frac{d ^{2} y}{d x ^{2}} = - \frac{y - x \frac{d y}{d x}}{y ^{2}}

Use equation \frac{d y}{d x} = - \frac{x}{y} to substitute

\frac{d ^{2} y}{d x ^{2}} = - \frac{y - x ( - \frac{x}{y} )}{y ^{2}}

Solution

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\frac{d ^{2} y}{d x ^{2}} = - \frac{y ^{2} + x ^{2}}{y ^{3}}

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Rewrite the equation

r = 1 r = - 1

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