Solve \frac{6}{x-1}+\frac{5}{x+1}=\frac{6}{x-1}

Pergunta

Solve the equation

x \in \emptyset

Alternative Form

Sem Solu \overset{c}{¸} \overset{a}{˜} o

Evaluate

\frac{6}{x - 1} + \frac{5}{x + 1} = \frac{6}{x - 1}

Find the domain

Mais Passos

\frac{6}{x - 1} + \frac{5}{x + 1} = \frac{6}{x - 1}, x \in (- \infty, - 1) \cup (- 1, 1) \cup (1, + \infty)

Multiply both sides of the equation by LCD

(\frac{6}{x - 1} + \frac{5}{x + 1}) (x - 1) (x + 1) = \frac{6}{x - 1} \times (x - 1) (x + 1)

Simplify the equation

Mais Passos

11 x + 1 = \frac{6}{x - 1} \times (x - 1) (x + 1)

Simplify the equation

Mais Passos

11 x + 1 = 6 x + 6

Move the expression to the left side

11 x + 1 - 6 x = 6

Move the expression to the right side

11 x - 6 x = 6 - 1

Add and subtract

Mais Passos

5 x = 6 - 1

Add and subtract

5 x = 5

Divide both sides

\frac{5 x}{5} = \frac{5}{5}

Divide the numbers

x = \frac{5}{5}

Divide the numbers

Mais Passos

x = 1

Check if the solution is in the defined range

x = 1, x \in (- \infty, - 1) \cup (- 1, 1) \cup (1, + \infty)

Solução

x \in \emptyset

Alternative Form

Sem Solu \overset{c}{¸} \overset{a}{˜} o

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