Question
Rewrite the parametric equations
x=92(y−2)2
Evaluate
{y=3t+2x=2t2
Choose the parametric equation
y=3t+2
Solve the equation
t=3y−2
Solution
x=92(y−2)2
Show Solution
Find the first derivative
dxdy=4t3
Evaluate
{y=3t+2x=2t2
To find the derivative dxdy,first find dtdx and dtdy
dtd(y)=dtd(3t+2)dtd(x)=dtd(2t2)
Find the derivative
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Evaluate
dtd(y)=dtd(3t+2)
Calculate the derivative
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Evaluate
dtd(y)
Use differentiation rules
dyd(y)×dtdy
Use dxdxn=nxn−1 to find derivative
dtdy
dtdy=dtd(3t+2)
Calculate the derivative
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Evaluate
dtd(3t+2)
Use differentiation rule dxd(f(x)±g(x))=dxd(f(x))±dxd(g(x))
dtd(3t)+dtd(2)
Calculate
3+dtd(2)
Use dxd(c)=0 to find derivative
3+0
Removing 0 doesn't change the value,so remove it from the expression
3
dtdy=3
dtdy=3dtd(x)=dtd(2t2)
Find the derivative
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Evaluate
dtd(x)=dtd(2t2)
Calculate the derivative
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Evaluate
dtd(x)
Use differentiation rules
dxd(x)×dtdx
Use dxdxn=nxn−1 to find derivative
dtdx
dtdx=dtd(2t2)
Calculate the derivative
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Evaluate
dtd(2t2)
Use differentiation rule dxd(cf(x))=c×dxd(f(x))
2×dtd(t2)
Use dxdxn=nxn−1 to find derivative
2×2t
Multiply the terms
4t
dtdx=4t
dtdy=3dtdx=4t
Solution
dxdy=4t3
Show Solution