Solve [3x-2]27x^3

Evaluate

(3 x - 2) \times 27 x^{3}

To find the roots of the expression,set the expression equal to 0

(3 x - 2) \times 27 x^{3} = 0

Multiply the first two terms

27 (3 x - 2) x^{3} = 0

Elimination the left coefficient

(3 x - 2) x^{3} = 0

Separate the equation into 2 possible cases

3 x - 2 = 0 x^{3} = 0

Solve the equation

More Steps

x = \frac{2}{3} x^{3} = 0

The only way a power can be 0 is when the base equals 0

x = \frac{2}{3} x = 0

Solution

x_{1} = 0, x_{2} = \frac{2}{3}

Alternative Form

x_{1} = 0, x_{2} = 0. \dot{6}

Simplify the expression