Algebra
Calculus
Trigonometry
Matrix
Question
Simplify the expression
x2−2x+12x−14
Evaluate
x−12×x−1x−7
Multiply the terms
(x−1)(x−1)2(x−7)
Multiply the terms
(x−1)22(x−7)
Multiply the terms
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Evaluate
2(x−7)
Apply the distributive property
2x−2×7
Multiply the numbers
2x−14
(x−1)22x−14
Solution
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Evaluate
(x−1)2
Use (a−b)2=a2−2ab+b2 to expand the expression
x2−2x×1+12
Calculate
x2−2x+1
x2−2x+12x−14
Show Solution
Find the excluded values
x=1
Evaluate
(x−12×x−1x−7)
To find the excluded values,set the denominators equal to 0
x−1=0
Move the constant to the right-hand side and change its sign
x=0+1
Solution
x=1
Show Solution
Find the roots
x=7
Evaluate
(x−12×x−1x−7)
To find the roots of the expression,set the expression equal to 0
x−12×x−1x−7=0
Find the domain
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Evaluate
x−1=0
Move the constant to the right side
x=0+1
Removing 0 doesn't change the value,so remove it from the expression
x=1
x−12×x−1x−7=0,x=1
Calculate
x−12×x−1x−7=0
Multiply the terms
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Multiply the terms
x−12×x−1x−7
Multiply the terms
(x−1)(x−1)2(x−7)
Multiply the terms
(x−1)22(x−7)
(x−1)22(x−7)=0
Cross multiply
2(x−7)=(x−1)2×0
Simplify the equation
2(x−7)=0
Rewrite the expression
x−7=0
Move the constant to the right side
x=0+7
Removing 0 doesn't change the value,so remove it from the expression
x=7
Check if the solution is in the defined range
x=7,x=1
Solution
x=7
Show Solution