Question
Evaluate the integral
x−2arctan(x)+C,C∈R
Evaluate
∫x2+1x2−1dx
Rewrite the fraction
∫(1−x2+12)dx
Use the property of integral ∫f(x)±g(x)dx=∫f(x)dx±∫g(x)dx
∫1dx+∫−x2+12dx
Use the property of integral ∫kdx=kx
x+∫−x2+12dx
Evaluate the integral
More Steps

Evaluate
∫−x2+12dx
Rewrite the expression
∫−2×x2+11dx
Use the property of integral ∫kf(x)dx=k∫f(x)dx
−2×∫x2+11dx
Use the property of integral ∫a2+x21dx=a1arctan(ax)
−2arctan(x)
x−2arctan(x)
Solution
x−2arctan(x)+C,C∈R
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