Question
Solve the equation
d=2b560−3b
Evaluate
d×32b5=20−b
Use the commutative property to reorder the terms
32db5=20−b
Rewrite the expression
32b5d=20−b
Divide both sides
32b532b5d=32b520−b
Divide the numbers
d=32b520−b
Solution
More Steps

Evaluate
32b520−b
Multiply by the reciprocal
(20−b)×2b53
To multiply the fractions,multiply the numerators and denominators separately
2b5(20−b)×3
Multiply the numbers
More Steps

Evaluate
(20−b)×3
Apply the distributive property
20×3−b×3
Multiply the numbers
60−b×3
Use the commutative property to reorder the terms
60−3b
2b560−3b
d=2b560−3b
Show Solution
