Question
Function
Find the first partial derivative with respect to m
Find the first partial derivative with respect to t
∂m∂ϵ=t1
Simplify
ϵ=tm−t
Find the first partial derivative by treating the variable t as a constant and differentiating with respect to m
∂m∂ϵ=∂m∂(tm−t)
Use differentiation rule ∂x∂(g(x)f(x))=(g(x))2∂x∂(f(x))×g(x)−f(x)×∂x∂(g(x))
∂m∂ϵ=t2∂m∂(m−t)t−(m−t)×∂m∂(t)
Evaluate
More Steps

Evaluate
∂m∂(m−t)
Use differentiation rule ∂x∂(f(x)±g(x))=∂x∂(f(x))±∂x∂(g(x))
∂m∂(m)−∂m∂(t)
Use ∂x∂xn=nxn−1 to find derivative
1−∂m∂(t)
Use ∂x∂(c)=0 to find derivative
1−0
Removing 0 doesn't change the value,so remove it from the expression
1
∂m∂ϵ=t21×t−(m−t)×∂m∂(t)
Use ∂x∂(c)=0 to find derivative
∂m∂ϵ=t21×t−(m−t)×0
Any expression multiplied by 1 remains the same
∂m∂ϵ=t2t−(m−t)×0
Any expression multiplied by 0 equals 0
∂m∂ϵ=t2t−0
Removing 0 doesn't change the value,so remove it from the expression
∂m∂ϵ=t2t
Solution
More Steps

Evaluate
t2t
Use the product rule aman=an−m to simplify the expression
t2−11
Reduce the fraction
t1
∂m∂ϵ=t1
Show Solution

Solve the equation
Solve for m
Solve for t
m=ϵt+t
Evaluate
ϵ=tm−t
Swap the sides of the equation
tm−t=ϵ
Cross multiply
m−t=tϵ
Simplify the equation
m−t=ϵt
Solution
m=ϵt+t
Show Solution
