Solve \frac{64t^2}{3t^{-2}} \cdot \frac{27t}{8t^{-1}}

Evaluate

\frac{64 t ^{2}}{3 t ^{- 2}} \times \frac{27 t}{8 t ^{- 1}}

To find the roots of the expression,set the expression equal to 0

\frac{64 t ^{2}}{3 t ^{- 2}} \times \frac{27 t}{8 t ^{- 1}} = 0

Find the domain

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\frac{64 t ^{2}}{3 t ^{- 2}} \times \frac{27 t}{8 t ^{- 1}} = 0, t \neq = 0

Calculate

\frac{64 t ^{2}}{3 t ^{- 2}} \times \frac{27 t}{8 t ^{- 1}} = 0

Divide the terms

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\frac{64 t ^{4}}{3} \times \frac{27 t}{8 t ^{- 1}} = 0

Divide the terms

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\frac{64 t ^{4}}{3} \times \frac{27 t ^{2}}{8} = 0

Multiply the terms

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72 t^{6} = 0

Rewrite the expression

t^{6} = 0

The only way a power can be 0 is when the base equals 0

t = 0

Check if the solution is in the defined range

t = 0, t \neq = 0

Solution

t \in \emptyset

Simplify the expression