Question
Evaluate the integral
5168x5+C,C∈R
Evaluate
∫4x3×2(7x×1)×3dx
Remove the parentheses
∫4x3×2×7x×1×3dx
Multiply the terms
More Steps

Multiply the terms
4x3×2×7x×1×3
Rewrite the expression
4x3×2×7x×3
Multiply the terms
More Steps

Evaluate
4×2×7×3
Multiply the terms
8×7×3
Multiply the terms
56×3
Multiply the numbers
168
168x3×x
Multiply the terms with the same base by adding their exponents
168x3+1
Add the numbers
168x4
∫168x4dx
Use the property of integral ∫kf(x)dx=k∫f(x)dx
168×∫x4dx
Use the property of integral ∫xndx=n+1xn+1
168×4+1x4+1
Simplify
More Steps

Evaluate
4+1x4+1
Add the numbers
4+1x5
Add the numbers
5x5
168×5x5
Multiply the terms
5168x5
Solution
5168x5+C,C∈R
Show Solution
