Question
Solve the equation
z1=−2+2i,z2=4+2i
Evaluate
∣z−1−2i∣=3
Separate the equation into 2 possible cases
z−1−2i=3z−1−2i=−3
Solve the equation for z
More Steps

Evaluate
z−1−2i=3
Move the constant to the right-hand side and change its sign
z=3+1+2i
Calculate
z=4+2i
z=4+2iz−1−2i=−3
Solve the equation for z
More Steps

Evaluate
z−1−2i=−3
Move the constant to the right-hand side and change its sign
z=−3+1+2i
Calculate
z=−2+2i
z=4+2iz=−2+2i
Solution
z1=−2+2i,z2=4+2i
Show Solution
