Question Solve the equation z1=−1+512i,z2=1+512i Evaluate ∣z−512i∣=1Separate the equation into 2 possible cases z−512i=1z−512i=−1Solve the equation for z z=1+512iz−512i=−1Solve the equation for z z=1+512iz=−1+512iSolution z1=−1+512i,z2=1+512i Show Solution
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