Solve 若3ª=15;5ª=15 求(a-1)(b-1)

Evaluate

{R u o \times 3 a = 15 5 a = 15 Q i u (a - 1) (b - 1)

Use the commutative property to reorder the terms

{3 R u o a = 15 5 a = 15 Q i u (a - 1) (b - 1)

Calculate

{3 R u o a = 15 5 a = 15 i Q u (a - 1) (b - 1)

Solve the equation for Q

More Steps

{3 R u o a = 15 Q = \frac{a}{- 3 ab u + 3 a u + 3 b u - 3 u} i

Substitute the given value of Q into the equation 3 R u o a = 15

3 R u o a = 15

Evaluate

3 u o a R = 15

Divide both sides

\frac{3 u o a R}{3 u o a} = \frac{15}{3 u o a}

Divide the numbers

R = \frac{15}{3 u o a}

Divide the numbers

More Steps

R = \frac{5}{o u a}

Solution

(Q, R, a, b, o, u) = (\frac{a}{- 3 ab u + 3 a u + 3 b u - 3 u} i, \frac{5}{o u a}, a, b, o, u), (u, o, a, b) \in R^{4}

Alternative Form

Infinitely many solutions

Solve the system of equations