Solve ( - 3h^3-2h^2-3h 8)-(6h^3-9h^2-3h)

Question

Simplify the expression

- 9 h^{3} + 7 h^{2} - 21 h

Show Solution

- h (9 h^{2} - 7 h + 21)

Show Solution

h_{1} = \frac{7}{18} - \frac{707}{18} i, h_{2} = \frac{7}{18} + \frac{707}{18} i, h_{3} = 0

Alternative Form

h_{1} \approx 0.3 \dot{8} - 1.477193 i, h_{2} \approx 0.3 \dot{8} + 1.477193 i, h_{3} = 0

Evaluate

(- 3 h^{3} - 2 h^{2} - 3 h \times 8) - (6 h^{3} - 9 h^{2} - 3 h)

To find the roots of the expression,set the expression equal to 0

(- 3 h^{3} - 2 h^{2} - 3 h \times 8) - (6 h^{3} - 9 h^{2} - 3 h) = 0

Multiply the terms

(- 3 h^{3} - 2 h^{2} - 24 h) - (6 h^{3} - 9 h^{2} - 3 h) = 0

Remove the parentheses

- 3 h^{3} - 2 h^{2} - 24 h - (6 h^{3} - 9 h^{2} - 3 h) = 0

Subtract the terms

More Steps

- 9 h^{3} + 7 h^{2} - 21 h = 0

Factor the expression

- h (9 h^{2} - 7 h + 21) = 0

Separate the equation into 2 possible cases

- h = 0 9 h^{2} - 7 h + 21 = 0

Change the signs on both sides of the equation

h = 0 9 h^{2} - 7 h + 21 = 0

Solve the equation

More Steps

h = 0 h = \frac{7}{18} + \frac{707}{18} i h = \frac{7}{18} - \frac{707}{18} i

Solution

h_{1} = \frac{7}{18} - \frac{707}{18} i, h_{2} = \frac{7}{18} + \frac{707}{18} i, h_{3} = 0

Alternative Form

h_{1} \approx 0.3 \dot{8} - 1.477193 i, h_{2} \approx 0.3 \dot{8} + 1.477193 i, h_{3} = 0

Show Solution