Question
Evaluate the derivative
x32ln(x)
Evaluate
((ln(1×x4))2)′
Any expression multiplied by 1 remains the same
((ln(x4))2)′
Rewrite the expression
dxd((ln(x4))2)
Use the chain rule dxd(f(g))=dgd(f(g))×dxd(g) where the g=ln(x4), to find the derivative
dgd(g2)×dxd(ln(x4))
Use dxdxn=nxn−1 to find derivative
2g×dxd(ln(x4))
Calculate
More Steps

Calculate
dxd(ln(x4))
Use the chain rule dxd(f(g))=dgd(f(g))×dxd(g) where the g=x4, to find the derivative
dgd(ln(g))×dxd(x4)
Use dxdlnx=x1 to find derivative
g1×dxd(x4)
Use dxdxn=nxn−1 to find derivative
g1×4x3
Substitute back
x41×4x3
Cancel out the common factor x3
x1×4
Multiply the terms
x4
2g×x4
Substitute back
2ln(x4)×x4
Multiply the terms
x2ln(x4)×4
Multiply the terms
x8ln(x4)
Use lnbn=nlnb to simplify the expression
x8×4ln(x)
Solution
x32ln(x)
Show Solution
