Question
Solve the equation
Solve for x
Solve for y
x=0x=−y2+1x=−−y2+1
Evaluate
(x2+y2−1)x2y3=0
Multiply the first two terms
x2(x2+y2−1)y3=0
Rewrite the expression
y3x2(x2+y2−1)=0
Elimination the left coefficient
x2(x2+y2−1)=0
Separate the equation into 2 possible cases
x2=0x2+y2−1=0
The only way a power can be 0 is when the base equals 0
x=0x2+y2−1=0
Solution
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Evaluate
x2+y2−1=0
Move the expression to the right-hand side and change its sign
x2=0−(y2−1)
Subtract the terms
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Evaluate
0−(y2−1)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
0−y2+1
Removing 0 doesn't change the value,so remove it from the expression
−y2+1
x2=−y2+1
Take the root of both sides of the equation and remember to use both positive and negative roots
x=±−y2+1
Separate the equation into 2 possible cases
x=−y2+1x=−−y2+1
x=0x=−y2+1x=−−y2+1
Show Solution

Testing for symmetry
Testing for symmetry about the origin
Testing for symmetry about the x-axis
Testing for symmetry about the y-axis
Symmetry with respect to the origin
Evaluate
(x2+y2−1)x2y3=0
Multiply the first two terms
x2(x2+y2−1)y3=0
To test if the graph of x2(x2+y2−1)y3=0 is symmetry with respect to the origin,substitute -x for x and -y for y
(−x)2((−x)2+(−y)2−1)(−y)3=0
Evaluate
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Evaluate
(−x)2((−x)2+(−y)2−1)(−y)3
Calculate the sum or difference
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Evaluate
(−x)2+(−y)2−1
Rewrite the expression
x2+(−y)2−1
Rewrite the expression
x2+y2−1
(−x)2(x2+y2−1)(−y)3
Multiply the terms
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Evaluate
(−x)2(−y)3
Rewrite the expression
x2(−y3)
Use the commutative property to reorder the terms
−x2y3
−x2y3(x2+y2−1)
−x2y3(x2+y2−1)=0
Solution
Symmetry with respect to the origin
Show Solution

Rewrite the equation
r=0r=1r=−1
Evaluate
(x2+y2−1)x2y3=0
Evaluate
x2(x2+y2−1)y3=0
Move the expression to the left side
x4y3+x2y5−x2y3=0
To convert the equation to polar coordinates,substitute x for rcos(θ) and y for rsin(θ)
(cos(θ)×r)4(sin(θ)×r)3+(cos(θ)×r)2(sin(θ)×r)5−(cos(θ)×r)2(sin(θ)×r)3=0
Factor the expression
(cos4(θ)sin3(θ)+cos2(θ)sin5(θ))r7−cos2(θ)sin3(θ)×r5=0
Simplify the expression
cos2(θ)sin3(θ)×r7−cos2(θ)sin3(θ)×r5=0
Factor the expression
r5((rcos(θ))2sin3(θ)−cos2(θ)sin3(θ))=0
When the product of factors equals 0,at least one factor is 0
r5=0(rcos(θ))2sin3(θ)−cos2(θ)sin3(θ)=0
Evaluate
r=0(rcos(θ))2sin3(θ)−cos2(θ)sin3(θ)=0
Solution
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Factor the expression
cos2(θ)sin3(θ)×r2−cos2(θ)sin3(θ)=0
Subtract the terms
cos2(θ)sin3(θ)×r2−cos2(θ)sin3(θ)−(−cos2(θ)sin3(θ))=0−(−cos2(θ)sin3(θ))
Evaluate
cos2(θ)sin3(θ)×r2=cos2(θ)sin3(θ)
Divide the terms
r2=1
Evaluate the power
r=±1
Simplify the expression
r=±1
Separate into possible cases
r=1r=−1
r=0r=1r=−1
Show Solution

Find the first derivative
Find the derivative with respect to x
Find the derivative with respect to y
dxdy=5xy2+3x3−3x−4x2y−2y3+2y
Calculate
(x2+y2−1)⋅x2y3=0
Simplify the expression
x2(x2+y2−1)y3=0
Take the derivative of both sides
dxd(x2(x2+y2−1)y3)=dxd(0)
Calculate the derivative
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Evaluate
dxd(x2(x2+y2−1)y3)
Use differentiation rules
dxd(x2)×(x2+y2−1)×y3+x2×dxd(x2+y2−1)×y3+x2(x2+y2−1)×dxd(y3)
Use dxdxn=nxn−1 to find derivative
2x3y3+2xy5−2xy3+x2×dxd(x2+y2−1)×y3+x2(x2+y2−1)×dxd(y3)
Evaluate the derivative
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Evaluate
dxd(x2+y2−1)
Use differentiation rules
dxd(x2)+dxd(y2)+dxd(−1)
Use dxdxn=nxn−1 to find derivative
2x+dxd(y2)+dxd(−1)
Evaluate the derivative
2x+2ydxdy+dxd(−1)
Use dxd(c)=0 to find derivative
2x+2ydxdy+0
Evaluate
2x+2ydxdy
2x3y3+2xy5−2xy3+2x3y3+2x2y4dxdy+x2(x2+y2−1)×dxd(y3)
Evaluate the derivative
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Evaluate
dxd(y3)
Use differentiation rules
dyd(y3)×dxdy
Use dxdxn=nxn−1 to find derivative
3y2dxdy
2x3y3+2xy5−2xy3+2x3y3+2x2y4dxdy+3x4y2dxdy+3x2y4dxdy−3x2y2dxdy
2x3y3+2xy5−2xy3+2x3y3+2x2y4dxdy+3x4y2dxdy+3x2y4dxdy−3x2y2dxdy=dxd(0)
Calculate the derivative
2x3y3+2xy5−2xy3+2x3y3+2x2y4dxdy+3x4y2dxdy+3x2y4dxdy−3x2y2dxdy=0
Calculate the sum or difference
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Evaluate
2x3y3+2xy5−2xy3+2x3y3+2x2y4dxdy+3x4y2dxdy+3x2y4dxdy−3x2y2dxdy
Add the terms
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Evaluate
2x3y3+2x3y3
Collect like terms by calculating the sum or difference of their coefficients
(2+2)x3y3
Add the numbers
4x3y3
4x3y3+2xy5−2xy3+2x2y4dxdy+3x4y2dxdy+3x2y4dxdy−3x2y2dxdy
Calculate the sum or difference
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Evaluate
2x2y4dxdy+3x4y2dxdy+3x2y4dxdy−3x2y2dxdy
Collect like terms by calculating the sum or difference of their coefficients
(2x2y4+3x4y2+3x2y4−3x2y2)dxdy
Add the terms
(5x2y4+3x4y2−3x2y2)dxdy
4x3y3+2xy5−2xy3+(5x2y4+3x4y2−3x2y2)dxdy
4x3y3+2xy5−2xy3+(5x2y4+3x4y2−3x2y2)dxdy=0
Move the constant to the right side
(5x2y4+3x4y2−3x2y2)dxdy=0−(4x3y3+2xy5−2xy3)
Subtract the terms
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Evaluate
0−(4x3y3+2xy5−2xy3)
Removing 0 doesn't change the value,so remove it from the expression
−(4x3y3+2xy5−2xy3)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
−4x3y3−2xy5+2xy3
(5x2y4+3x4y2−3x2y2)dxdy=−4x3y3−2xy5+2xy3
Divide both sides
5x2y4+3x4y2−3x2y2(5x2y4+3x4y2−3x2y2)dxdy=5x2y4+3x4y2−3x2y2−4x3y3−2xy5+2xy3
Divide the numbers
dxdy=5x2y4+3x4y2−3x2y2−4x3y3−2xy5+2xy3
Solution
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Evaluate
5x2y4+3x4y2−3x2y2−4x3y3−2xy5+2xy3
Rewrite the expression
5x2y4+3x4y2−3x2y2xy2(−4x2y−2y3+2y)
Rewrite the expression
xy2(5xy2+3x3−3x)xy2(−4x2y−2y3+2y)
Reduce the fraction
5xy2+3x3−3x−4x2y−2y3+2y
dxdy=5xy2+3x3−3x−4x2y−2y3+2y
Show Solution
