Solve (1 x^2)dy^2xy =4x^2

Evaluate

(1 \times x^{2}) d y^{2} x y = 4 x^{2}

Remove the parentheses

1 \times x^{2} d y^{2} x y = 4 x^{2}

Multiply the terms

More Steps

x^{3} d y^{3} = 4 x^{2}

Rewrite the expression

d y^{3} x^{3} = 4 x^{2}

Add or subtract both sides

d y^{3} x^{3} - 4 x^{2} = 0

Factor the expression

x^{2} (d y^{3} x - 4) = 0

Separate the equation into 2 possible cases

x^{2} = 0 d y^{3} x - 4 = 0

The only way a power can be 0 is when the base equals 0

x = 0 d y^{3} x - 4 = 0

Solution

More Steps

x = 0 x = \frac{4}{d y ^{3}}

Solve the equation