Question
Simplify the expression
4v23−28v2
Evaluate
(3×2v1)2v1−7
Remove the parentheses
3×2v12v1−7
Multiply the terms
2v32v1−7
Divide the terms
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Evaluate
2v32v
Multiply by the reciprocal
2v×32v
Multiply the terms
32v×2v
Multiply the terms
More Steps

Evaluate
2v×2v
Multiply the numbers
4v×v
Multiply the terms
4v2
34v2
34v21−7
Divide the terms
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Evaluate
34v21
Multiply by the reciprocal
1×4v23
Any expression multiplied by 1 remains the same
4v23
4v23−7
Reduce fractions to a common denominator
4v23−4v27×4v2
Write all numerators above the common denominator
4v23−7×4v2
Solution
4v23−28v2
Show Solution

Find the excluded values
v=0
Evaluate
(3×2v1)2v1−7
To find the excluded values,set the denominators equal to 0
2v=03×2v1=0(3×2v1)2v=0
Solve the equations
v=03×2v1=0(3×2v1)2v=0
Solve the equations
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Evaluate
3×2v1=0
Multiply the terms
2v3=0
Cross multiply
3=2v×0
Simplify the equation
3=0
The statement is false for any value of v
v∈∅
v=0v∈∅(3×2v1)2v=0
Solve the equations
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Evaluate
(3×2v1)2v=0
Remove the parentheses
3×2v12v=0
Simplify
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Evaluate
3×2v12v
Multiply the terms
2v32v
Multiply by the reciprocal
2v×32v
Multiply the terms
32v×2v
Multiply the terms
34v2
34v2=0
Simplify
4v2=0
Rewrite the expression
v2=0
The only way a power can be 0 is when the base equals 0
v=0
v=0v∈∅v=0
Solution
v=0
Show Solution

Find the roots
v1=−1421,v2=1421
Alternative Form
v1≈−0.327327,v2≈0.327327
Evaluate
(3×2v1)2v1−7
To find the roots of the expression,set the expression equal to 0
(3×2v1)2v1−7=0
Find the domain
More Steps

Evaluate
⎩⎨⎧2v=03×2v1=0(3×2v1)2v=0
Calculate
⎩⎨⎧v=03×2v1=0(3×2v1)2v=0
Calculate
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Evaluate
3×2v1=0
Multiply the terms
2v3=0
Multiply both sides
2v3×2v=0×2v
Evaluate
3=0×2v
Multiply both sides
3=0
The statement is true for any value of v
v∈R
⎩⎨⎧v=0v∈R(3×2v1)2v=0
Calculate
More Steps

Evaluate
(3×2v1)2v=0
Remove the parentheses
3×2v12v=0
Simplify
34v2=0
Simplify
4v2=0
Rewrite the expression
v2=0
The only way a power can not be 0 is when the base not equals 0
v=0
⎩⎨⎧v=0v∈Rv=0
Simplify
{v=0v∈R
Find the intersection
v=0
(3×2v1)2v1−7=0,v=0
Calculate
(3×2v1)2v1−7=0
Multiply the terms
2v32v1−7=0
Divide the terms
More Steps

Evaluate
2v32v
Multiply by the reciprocal
2v×32v
Multiply the terms
32v×2v
Multiply the terms
More Steps

Evaluate
2v×2v
Multiply the numbers
4v×v
Multiply the terms
4v2
34v2
34v21−7=0
Divide the terms
More Steps

Evaluate
34v21
Multiply by the reciprocal
1×4v23
Any expression multiplied by 1 remains the same
4v23
4v23−7=0
Subtract the terms
More Steps

Simplify
4v23−7
Reduce fractions to a common denominator
4v23−4v27×4v2
Write all numerators above the common denominator
4v23−7×4v2
Multiply the terms
4v23−28v2
4v23−28v2=0
Cross multiply
3−28v2=4v2×0
Simplify the equation
3−28v2=0
Rewrite the expression
−28v2=−3
Change the signs on both sides of the equation
28v2=3
Divide both sides
2828v2=283
Divide the numbers
v2=283
Take the root of both sides of the equation and remember to use both positive and negative roots
v=±283
Simplify the expression
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Evaluate
283
To take a root of a fraction,take the root of the numerator and denominator separately
283
Simplify the radical expression
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Evaluate
28
Write the expression as a product where the root of one of the factors can be evaluated
4×7
Write the number in exponential form with the base of 2
22×7
The root of a product is equal to the product of the roots of each factor
22×7
Reduce the index of the radical and exponent with 2
27
273
Multiply by the Conjugate
27×73×7
Multiply the numbers
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Evaluate
3×7
The product of roots with the same index is equal to the root of the product
3×7
Calculate the product
21
27×721
Multiply the numbers
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Evaluate
27×7
When a square root of an expression is multiplied by itself,the result is that expression
2×7
Multiply the terms
14
1421
v=±1421
Separate the equation into 2 possible cases
v=1421v=−1421
Check if the solution is in the defined range
v=1421v=−1421,v=0
Find the intersection of the solution and the defined range
v=1421v=−1421
Solution
v1=−1421,v2=1421
Alternative Form
v1≈−0.327327,v2≈0.327327
Show Solution
