Question
Find the excluded values
g=29
Evaluate
2g−910g3−11g2−129g−117
To find the excluded values,set the denominators equal to 0
2g−9=0
Move the constant to the right-hand side and change its sign
2g=0+9
Removing 0 doesn't change the value,so remove it from the expression
2g=9
Divide both sides
22g=29
Solution
g=29
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Divide the polynomials
5g2+17g+12+2g−9−9
Evaluate
2g−910g3−11g2−129g−117
Solution
5g2+17g+12+2g−9−9
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Find the roots
g1≈−2.298004,g2≈−1.125531,g3≈4.523534
Evaluate
2g−910g3−11g2−129g−117
To find the roots of the expression,set the expression equal to 0
2g−910g3−11g2−129g−117=0
Find the domain
More Steps

Evaluate
2g−9=0
Move the constant to the right side
2g=0+9
Removing 0 doesn't change the value,so remove it from the expression
2g=9
Divide both sides
22g=29
Divide the numbers
g=29
2g−910g3−11g2−129g−117=0,g=29
Calculate
2g−910g3−11g2−129g−117=0
Cross multiply
10g3−11g2−129g−117=(2g−9)×0
Simplify the equation
10g3−11g2−129g−117=0
Calculate
g≈4.523534g≈−2.298004g≈−1.125531
Check if the solution is in the defined range
g≈4.523534g≈−2.298004g≈−1.125531,g=29
Find the intersection of the solution and the defined range
g≈4.523534g≈−2.298004g≈−1.125531
Solution
g1≈−2.298004,g2≈−1.125531,g3≈4.523534
Show Solution
