Solve (14y+21)(18-3y)=0

Question

Solve the quadratic equation

Solve by factoring

Solve using the quadratic formula

Solve by completing the square

y_{1} = - \frac{3}{2}, y_{2} = 6

Alternative Form

y_{1} = - 1.5, y_{2} = 6

Evaluate

(14 y + 21) (18 - 3 y) = 0

When the product of factors equals 0,at least one factor is 0

18 - 3 y = 0 14 y + 21 = 0

Solve the equation for y

More Steps

Evaluate

18 - 3 y = 0

Move the constant to the right-hand side and change its sign

- 3 y = 0 - 18

Removing 0 doesn't change the value,so remove it from the expression

- 3 y = - 18

Change the signs on both sides of the equation

3 y = 18

Divide both sides

\frac{3 y}{3} = \frac{18}{3}

Divide the numbers

y = \frac{18}{3}

Divide the numbers

More Steps

Evaluate

\frac{18}{3}

Reduce the numbers

\frac{6}{1}

Calculate

6

y = 6

y = 6 14 y + 21 = 0

Solve the equation for y

More Steps

Evaluate

14 y + 21 = 0

Move the constant to the right-hand side and change its sign

14 y = 0 - 21

Removing 0 doesn't change the value,so remove it from the expression

14 y = - 21

Divide both sides

\frac{14 y}{14} = \frac{- 21}{14}

Divide the numbers

y = \frac{- 21}{14}

Divide the numbers

More Steps

Evaluate

\frac{- 21}{14}

Cancel out the common factor 7

\frac{- 3}{2}

Use \frac{- a}{b} = \frac{a}{- b} = - \frac{a}{b} to rewrite the fraction

- \frac{3}{2}

y = - \frac{3}{2}

y = 6 y = - \frac{3}{2}

Solution

y_{1} = - \frac{3}{2}, y_{2} = 6

Alternative Form

y_{1} = - 1.5, y_{2} = 6

Show Solution