Solve (2/b^2) 5=2

Evaluate

\frac{2}{b ^{2}} \times 5 = 2

Find the domain

More Steps

\frac{2}{b ^{2}} \times 5 = 2, b \neq = 0

Multiply the terms

More Steps

\frac{10}{b ^{2}} = 2

Cross multiply

10 = b^{2} \times 2

Simplify the equation

10 = 2 b^{2}

Rewrite the expression

2 \times 5 = 2 b^{2}

Evaluate

5 = b^{2}

Swap the sides of the equation

b^{2} = 5

Take the root of both sides of the equation and remember to use both positive and negative roots

b = \pm 5

Separate the equation into 2 possible cases

b = 5 b = - 5

Check if the solution is in the defined range

b = 5 b = - 5, b \neq = 0

Find the intersection of the solution and the defined range

b = 5 b = - 5

Solution

b_{1} = - 5, b_{2} = 5

Alternative Form

b_{1} \approx - 2.236068, b_{2} \approx 2.236068

Solve the equation