Solve (2-x)^2 2(2-x) 1

Question

Simplify the expression

16 - 24 x + 12 x^{2} - 2 x^{3}

Evaluate

(2 - x)^{2} \times 2 (2 - x) \times 1

Rewrite the expression

(2 - x)^{2} \times 2 (2 - x)

Multiply the terms with the same base by adding their exponents

(2 - x)^{2 + 1} \times 2

Add the numbers

(2 - x)^{3} \times 2

Use the commutative property to reorder the terms

2 (2 - x)^{3}

Expand the expression

More Steps

Evaluate

(2 - x)^{3}

Use (a - b)^{3} = a^{3} - 3 a^{2} b + 3 a b^{2} - b^{3} to expand the expression

2^{3} - 3 \times 2^{2} x + 3 \times 2 x^{2} - x^{3}

Calculate

8 - 12 x + 6 x^{2} - x^{3}

2 (8 - 12 x + 6 x^{2} - x^{3})

Apply the distributive property

2 \times 8 - 2 \times 12 x + 2 \times 6 x^{2} - 2 x^{3}

Multiply the numbers

16 - 2 \times 12 x + 2 \times 6 x^{2} - 2 x^{3}

Multiply the numbers

16 - 24 x + 2 \times 6 x^{2} - 2 x^{3}

Solution

16 - 24 x + 12 x^{2} - 2 x^{3}

Show Solution

x = 2

Evaluate

(2 - x)^{2} \times 2 (2 - x) \times 1

To find the roots of the expression,set the expression equal to 0

(2 - x)^{2} \times 2 (2 - x) \times 1 = 0

Multiply the terms

More Steps

Multiply the terms

(2 - x)^{2} \times 2 (2 - x) \times 1

Rewrite the expression

(2 - x)^{2} \times 2 (2 - x)

Multiply the terms with the same base by adding their exponents

(2 - x)^{2 + 1} \times 2

Add the numbers

(2 - x)^{3} \times 2

Use the commutative property to reorder the terms

2 (2 - x)^{3}

2 (2 - x)^{3} = 0

Rewrite the expression

(2 - x)^{3} = 0

The only way a power can be 0 is when the base equals 0

2 - x = 0

Move the constant to the right-hand side and change its sign

- x = 0 - 2

Removing 0 doesn't change the value,so remove it from the expression

- x = - 2

Solution

x = 2

Show Solution