Solve (233x) (8x-41)=15 (5x^3)

Question

Solve the equation

x_{1} = 0, x_{2} = \frac{932 - 152149}{75}, x_{3} = \frac{932 + 152149}{75}

Alternative Form

x_{1} = 0, x_{2} \approx 7.225829, x_{3} \approx 17.627504

Evaluate

233 x (8 x - 41) = 15 \times 5 x^{3}

Multiply the numbers

233 x (8 x - 41) = 75 x^{3}

Expand the expression

More Steps

1864 x^{2} - 9553 x = 75 x^{3}

Move the expression to the left side

1864 x^{2} - 9553 x - 75 x^{3} = 0

Factor the expression

x (1864 x - 9553 - 75 x^{2}) = 0

Separate the equation into 2 possible cases

x = 0 1864 x - 9553 - 75 x^{2} = 0

Solve the equation

More Steps

x = 0 x = \frac{932 + 152149}{75} x = \frac{932 - 152149}{75}

Solution

x_{1} = 0, x_{2} = \frac{932 - 152149}{75}, x_{3} = \frac{932 + 152149}{75}

Alternative Form

x_{1} = 0, x_{2} \approx 7.225829, x_{3} \approx 17.627504

Show Solution