Algebra
Calculus
Trigonometry
Matrix
Question
Simplify the expression
4p3−4p2
Evaluate
(2p−2)×2p2
Multiply the terms
2p2(2p−2)
Apply the distributive property
2p2×2p−2p2×2
Multiply the terms
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Evaluate
2p2×2p
Multiply the numbers
4p2×p
Multiply the terms
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Evaluate
p2×p
Use the product rule an×am=an+m to simplify the expression
p2+1
Add the numbers
p3
4p3
4p3−2p2×2
Solution
4p3−4p2
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Factor the expression
4p2(p−1)
Evaluate
(2p−2)×2p2
Multiply the terms
2p2(2p−2)
Factor the expression
2p2×2(p−1)
Solution
4p2(p−1)
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Find the roots
p1=0,p2=1
Evaluate
(2p−2)(2p2)
To find the roots of the expression,set the expression equal to 0
(2p−2)(2p2)=0
Multiply the terms
(2p−2)×2p2=0
Multiply the terms
2p2(2p−2)=0
Elimination the left coefficient
p2(2p−2)=0
Separate the equation into 2 possible cases
p2=02p−2=0
The only way a power can be 0 is when the base equals 0
p=02p−2=0
Solve the equation
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Evaluate
2p−2=0
Move the constant to the right-hand side and change its sign
2p=0+2
Removing 0 doesn't change the value,so remove it from the expression
2p=2
Divide both sides
22p=22
Divide the numbers
p=22
Divide the numbers
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Evaluate
22
Reduce the numbers
11
Calculate
1
p=1
p=0p=1
Solution
p1=0,p2=1
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