Algebra
Calculus
Trigonometry
Matrix
Question
Simplify the expression
6t4−12t3
Evaluate
(2t−4)×3t3
Multiply the terms
3t3(2t−4)
Apply the distributive property
3t3×2t−3t3×4
Multiply the terms
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Evaluate
3t3×2t
Multiply the numbers
6t3×t
Multiply the terms
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Evaluate
t3×t
Use the product rule an×am=an+m to simplify the expression
t3+1
Add the numbers
t4
6t4
6t4−3t3×4
Solution
6t4−12t3
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Factor the expression
6t3(t−2)
Evaluate
(2t−4)×3t3
Multiply the terms
3t3(2t−4)
Factor the expression
3t3×2(t−2)
Solution
6t3(t−2)
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Find the roots
t1=0,t2=2
Evaluate
(2t−4)(3t3)
To find the roots of the expression,set the expression equal to 0
(2t−4)(3t3)=0
Multiply the terms
(2t−4)×3t3=0
Multiply the terms
3t3(2t−4)=0
Elimination the left coefficient
t3(2t−4)=0
Separate the equation into 2 possible cases
t3=02t−4=0
The only way a power can be 0 is when the base equals 0
t=02t−4=0
Solve the equation
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Evaluate
2t−4=0
Move the constant to the right-hand side and change its sign
2t=0+4
Removing 0 doesn't change the value,so remove it from the expression
2t=4
Divide both sides
22t=24
Divide the numbers
t=24
Divide the numbers
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Evaluate
24
Reduce the numbers
12
Calculate
2
t=2
t=0t=2
Solution
t1=0,t2=2
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