Solve (2x^2 11x 12) (6x^2-3x-4)

Evaluate

(2 x^{2} \times 11 x \times 12) (6 x^{2} - 3 x - 4)

To find the roots of the expression,set the expression equal to 0

(2 x^{2} \times 11 x \times 12) (6 x^{2} - 3 x - 4) = 0

Multiply

More Steps

264 x^{3} (6 x^{2} - 3 x - 4) = 0

Elimination the left coefficient

x^{3} (6 x^{2} - 3 x - 4) = 0

Separate the equation into 2 possible cases

x^{3} = 0 6 x^{2} - 3 x - 4 = 0

The only way a power can be 0 is when the base equals 0

x = 0 6 x^{2} - 3 x - 4 = 0

Solve the equation

More Steps

x = 0 x = \frac{3 + 105}{12} x = \frac{3 - 105}{12}

Solution

x_{1} = \frac{3 - 105}{12}, x_{2} = 0, x_{3} = \frac{3 + 105}{12}

Alternative Form

x_{1} \approx - 0.603913, x_{2} = 0, x_{3} \approx 1.103913

Simplify the expression