Solve (2x^2-4)-(x^2-5x x-5)

Question

Simplify the expression

6 x^{2} + 1

Show Solution

x_{1} = - \frac{6}{6} i, x_{2} = \frac{6}{6} i

Alternative Form

x_{1} \approx - 0.408248 i, x_{2} \approx 0.408248 i

Evaluate

(2 x^{2} - 4) - (x^{2} - 5 x \times x - 5)

To find the roots of the expression,set the expression equal to 0

(2 x^{2} - 4) - (x^{2} - 5 x \times x - 5) = 0

Remove the parentheses

2 x^{2} - 4 - (x^{2} - 5 x \times x - 5) = 0

Multiply the terms

2 x^{2} - 4 - (x^{2} - 5 x^{2} - 5) = 0

Subtract the terms

More Steps

2 x^{2} - 4 - (- 4 x^{2} - 5) = 0

Subtract the terms

More Steps

6 x^{2} + 1 = 0

Move the constant to the right-hand side and change its sign

6 x^{2} = 0 - 1

Removing 0 doesn't change the value,so remove it from the expression

6 x^{2} = - 1

Divide both sides

\frac{6 x ^{2}}{6} = \frac{- 1}{6}

Divide the numbers

x^{2} = \frac{- 1}{6}

Use \frac{- a}{b} = \frac{a}{- b} = - \frac{a}{b} to rewrite the fraction

x^{2} = - \frac{1}{6}

Take the root of both sides of the equation and remember to use both positive and negative roots

x = \pm - \frac{1}{6}

Simplify the expression

More Steps

x = \pm \frac{6}{6} i

Separate the equation into 2 possible cases

x = \frac{6}{6} i x = - \frac{6}{6} i

Solution

x_{1} = - \frac{6}{6} i, x_{2} = \frac{6}{6} i

Alternative Form

x_{1} \approx - 0.408248 i, x_{2} \approx 0.408248 i

Show Solution