Question
Solve the quadratic equation
Solve by factoring
Solve using the quadratic formula
Solve by completing the square
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x1=−46,x2=52
Evaluate
(2x−4)(x−4)=4800
Expand the expression
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Evaluate
(2x−4)(x−4)
Apply the distributive property
2x×x−2x×4−4x−(−4×4)
Multiply the terms
2x2−2x×4−4x−(−4×4)
Multiply the numbers
2x2−8x−4x−(−4×4)
Multiply the numbers
2x2−8x−4x−(−16)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
2x2−8x−4x+16
Subtract the terms
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Evaluate
−8x−4x
Collect like terms by calculating the sum or difference of their coefficients
(−8−4)x
Subtract the numbers
−12x
2x2−12x+16
2x2−12x+16=4800
Move the expression to the left side
2x2−12x−4784=0
Factor the expression
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Evaluate
2x2−12x−4784
Rewrite the expression
2x2−2×6x−2×2392
Factor out 2 from the expression
2(x2−6x−2392)
Factor the expression
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Evaluate
x2−6x−2392
Rewrite the expression
x2+(46−52)x−2392
Calculate
x2+46x−52x−2392
Rewrite the expression
x×x+x×46−52x−52×46
Factor out x from the expression
x(x+46)−52x−52×46
Factor out −52 from the expression
x(x+46)−52(x+46)
Factor out x+46 from the expression
(x−52)(x+46)
2(x−52)(x+46)
2(x−52)(x+46)=0
Divide the terms
(x−52)(x+46)=0
When the product of factors equals 0,at least one factor is 0
x−52=0x+46=0
Solve the equation for x
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Evaluate
x−52=0
Move the constant to the right-hand side and change its sign
x=0+52
Removing 0 doesn't change the value,so remove it from the expression
x=52
x=52x+46=0
Solve the equation for x
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Evaluate
x+46=0
Move the constant to the right-hand side and change its sign
x=0−46
Removing 0 doesn't change the value,so remove it from the expression
x=−46
x=52x=−46
Solution
x1=−46,x2=52
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