Algebra
Calculus
Trigonometry
Matrix
Question
Solve the equation
Solve for x
Solve for y
Solve for z
x=2yz
Evaluate
(2x−yz)2×22y2−z×(z−4)1×2=0
Simplify
More Steps
Evaluate
(2x−yz)2×22y2−z×(z−4)1×2
Calculate
(2x−yz)2×22y2−z×(z−4)×2
Multiply the terms
(2x−yz)2×44y2−z×(z−4)
Use the commutative property to reorder the terms
44(2x−yz)2y2−z×(z−4)
44(2x−yz)2y2−z×(z−4)=0
Rewrite the expression
(44zy2−z−176y2−z)(2x−yz)2=0
Rewrite the expression
(2x−yz)2=0
The only way a power can be 0 is when the base equals 0
2x−yz=0
Move the expression to the right-hand side and change its sign
2x=0+yz
Add the terms
2x=yz
Divide both sides
22x=2yz
Solution
x=2yz
Show Solution
