Question
Solve the equation
k1=0,k2=2
Evaluate
(3k−6)k2=0
Multiply the terms
k2(3k−6)=0
Separate the equation into 2 possible cases
k2=03k−6=0
The only way a power can be 0 is when the base equals 0
k=03k−6=0
Solve the equation
More Steps

Evaluate
3k−6=0
Move the constant to the right-hand side and change its sign
3k=0+6
Removing 0 doesn't change the value,so remove it from the expression
3k=6
Divide both sides
33k=36
Divide the numbers
k=36
Divide the numbers
More Steps

Evaluate
36
Reduce the numbers
12
Calculate
2
k=2
k=0k=2
Solution
k1=0,k2=2
Show Solution
