Algebra
Calculus
Trigonometry
Matrix
Question
Simplify the expression
6v5−12v4
Evaluate
3v4(2v−4)
Apply the distributive property
3v4×2v−3v4×4
Multiply the terms
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Evaluate
3v4×2v
Multiply the numbers
6v4×v
Multiply the terms
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Evaluate
v4×v
Use the product rule an×am=an+m to simplify the expression
v4+1
Add the numbers
v5
6v5
6v5−3v4×4
Solution
6v5−12v4
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Factor the expression
6v4(v−2)
Evaluate
3v4(2v−4)
Factor the expression
3v4×2(v−2)
Solution
6v4(v−2)
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Find the roots
v1=0,v2=2
Evaluate
(3v4)(2v−4)
To find the roots of the expression,set the expression equal to 0
(3v4)(2v−4)=0
Multiply the terms
3v4(2v−4)=0
Elimination the left coefficient
v4(2v−4)=0
Separate the equation into 2 possible cases
v4=02v−4=0
The only way a power can be 0 is when the base equals 0
v=02v−4=0
Solve the equation
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Evaluate
2v−4=0
Move the constant to the right-hand side and change its sign
2v=0+4
Removing 0 doesn't change the value,so remove it from the expression
2v=4
Divide both sides
22v=24
Divide the numbers
v=24
Divide the numbers
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Evaluate
24
Reduce the numbers
12
Calculate
2
v=2
v=0v=2
Solution
v1=0,v2=2
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